2n^2+4n-1600=0

Solution for 2n^2+4n-1600=0 equation:

2n^2+4n-1600=0

a = 2; b = 4; c = -1600;
Δ = b2-4ac
Δ = 42-4·2·(-1600)
Δ = 12816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12816}=\sqrt{144*89}=\sqrt{144}*\sqrt{89}=12\sqrt{89}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12\sqrt{89}}{2*2}=\frac{-4-12\sqrt{89}}{4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12\sqrt{89}}{2*2}=\frac{-4+12\sqrt{89}}{4}
$